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#include "Kaleidoscope.h"
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static uint8_t DefaultLayer;
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static uint32_t LayerState;
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uint8_t Layer_::highestLayer;
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Key Layer_::keyMap[ROWS][COLS];
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Key(*Layer_::getKey)(uint8_t layer, byte row, byte col) = Layer.getKeyFromPROGMEM;
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static void handleKeymapKeyswitchEvent(Key keymapEntry, uint8_t keyState) {
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if (keymapEntry.keyCode >= MOMENTARY_OFFSET) {
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uint8_t target = keymapEntry.keyCode - MOMENTARY_OFFSET;
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if (keyToggledOn(keyState)) {
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if (target == KEYMAP_NEXT) {
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Layer.next();
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} else if (target == KEYMAP_PREVIOUS) {
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Layer.previous();
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} else {
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Layer.on(target);
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}
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}
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if (keyToggledOff(keyState)) {
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if (target == KEYMAP_NEXT) {
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Layer.previous();
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} else if (target == KEYMAP_PREVIOUS) {
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Layer.next();
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} else {
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Layer.off(target);
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}
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}
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// switch keymap and stay there
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} else if (keyToggledOn(keyState)) {
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if (Layer.isOn(keymapEntry.keyCode) && keymapEntry.keyCode)
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Layer.off(keymapEntry.keyCode);
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else
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Layer.on(keymapEntry.keyCode);
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}
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}
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Key
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Layer_::eventHandler(Key mappedKey, byte row, byte col, uint8_t keyState) {
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if (mappedKey.flags != (SYNTHETIC | SWITCH_TO_KEYMAP))
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return mappedKey;
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handleKeymapKeyswitchEvent(mappedKey, keyState);
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return Key_NoKey;
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}
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Layer_::Layer_(void) {
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defaultLayer(0);
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}
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Key
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Layer_::getKeyFromPROGMEM(uint8_t layer, byte row, byte col) {
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Key key;
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key.raw = pgm_read_word(&(keymaps[layer][row][col]));
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return key;
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}
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Cache the keymap when changing layers
Instead of going through all the active layers each time we are looking for a
key, whenever we switch layers, compute the effective keymap, and store the
indexes. This makes the lookup a considerably faster operation, and lookups
happen far more often than layer switching.
This comes at a cost of ROWS*COLS amount of memory, and a bit of code, but on
the flip side, the lookup operation is now O(1), which is a very nice property
to have, if you want responsiveness. Changing layers is marginally slower,
however, but even with 32 active layers, doing the computation once, instead of
potentially many dozens of time, is still worth it.
We could further reduce the memory requirements if we stored more columns per
byte, but that's for a future optimization.
Signed-off-by: Gergely Nagy <algernon@madhouse-project.org>
8 years ago
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void
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Layer_::updateKeyCache(byte row, byte col) {
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int8_t layer = highestLayer;
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Cache the keymap when changing layers
Instead of going through all the active layers each time we are looking for a
key, whenever we switch layers, compute the effective keymap, and store the
indexes. This makes the lookup a considerably faster operation, and lookups
happen far more often than layer switching.
This comes at a cost of ROWS*COLS amount of memory, and a bit of code, but on
the flip side, the lookup operation is now O(1), which is a very nice property
to have, if you want responsiveness. Changing layers is marginally slower,
however, but even with 32 active layers, doing the computation once, instead of
potentially many dozens of time, is still worth it.
We could further reduce the memory requirements if we stored more columns per
byte, but that's for a future optimization.
Signed-off-by: Gergely Nagy <algernon@madhouse-project.org>
8 years ago
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if (row >= ROWS || col >= COLS)
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return;
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for (layer = highestLayer; layer >= DefaultLayer; layer--) {
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if (Layer.isOn(layer)) {
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Key mappedKey = (*getKey)(layer, row, col);
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if (mappedKey != Key_Transparent) {
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keyMap[row][col] = mappedKey;
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break;
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}
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}
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}
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Cache the keymap when changing layers
Instead of going through all the active layers each time we are looking for a
key, whenever we switch layers, compute the effective keymap, and store the
indexes. This makes the lookup a considerably faster operation, and lookups
happen far more often than layer switching.
This comes at a cost of ROWS*COLS amount of memory, and a bit of code, but on
the flip side, the lookup operation is now O(1), which is a very nice property
to have, if you want responsiveness. Changing layers is marginally slower,
however, but even with 32 active layers, doing the computation once, instead of
potentially many dozens of time, is still worth it.
We could further reduce the memory requirements if we stored more columns per
byte, but that's for a future optimization.
Signed-off-by: Gergely Nagy <algernon@madhouse-project.org>
8 years ago
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}
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void
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Layer_::updateKeyCache(void) {
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for (byte row = 0; row < ROWS; row++) {
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for (byte col = 0; col < COLS; col++) {
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updateKeyCache(row, col);
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}
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}
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}
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uint8_t Layer_::top(void) {
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for (int8_t i = 31; i >= 0; i--) {
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if (bitRead(LayerState, i))
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return i;
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}
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return 0;
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}
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void Layer_::move(uint8_t layer) {
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LayerState = 0;
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on(layer);
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}
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void Layer_::on(uint8_t layer) {
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bitSet(LayerState, layer);
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if (layer > highestLayer)
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highestLayer = layer;
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// Update the key cache, so that if anything depends on knowing the active
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// layout, the layout will be in sync.
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updateKeyCache();
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}
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void Layer_::off(uint8_t layer) {
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bitClear(LayerState, layer);
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if (layer == highestLayer)
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highestLayer = top();
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// Update the key cache, so that if anything depends on knowing the active
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// layout, the layout will be in sync.
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updateKeyCache();
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}
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boolean Layer_::isOn(uint8_t layer) {
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return bitRead(LayerState, layer);
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}
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void Layer_::next(void) {
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on(top() + 1);
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}
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void Layer_::previous(void) {
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off(top());
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}
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void Layer_::defaultLayer(uint8_t layer) {
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move(layer);
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DefaultLayer = layer;
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}
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uint8_t Layer_::defaultLayer(void) {
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return DefaultLayer;
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}
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uint32_t Layer_::getLayerState(void) {
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return LayerState;
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}
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Layer_ Layer;
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