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97 lines
3.7 KiB
97 lines
3.7 KiB
#!/usr/bin/env python3
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# -*- coding: utf-8 -*-
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# ------------------------------------------------------------------------------
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# Copyright (c) 2022 Michael Richters <gedankenexperimenter@gmail.com>
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# This is free and unencumbered software released into the public domain.
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# Anyone is free to copy, modify, publish, use, compile, sell, or
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# distribute this software, either in source code form or as a compiled
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# binary, for any purpose, commercial or non-commercial, and by any
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# means.
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# In jurisdictions that recognize copyright laws, the author or authors
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# of this software dedicate any and all copyright interest in the
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# software to the public domain. We make this dedication for the benefit
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# of the public at large and to the detriment of our heirs and
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# successors. We intend this dedication to be an overt act of
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# relinquishment in perpetuity of all present and future rights to this
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# software under copyright law.
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# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND,
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# EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF
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# MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT.
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# IN NO EVENT SHALL THE AUTHORS BE LIABLE FOR ANY CLAIM, DAMAGES OR
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# OTHER LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE,
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# ARISING FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR
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# OTHER DEALINGS IN THE SOFTWARE.
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# For more information, please refer to <http://unlicense.org/>
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# ------------------------------------------------------------------------------
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"""When building Kaleidoscope, the compiled object files are linked together
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into a static archive. This static archive has a very simple structure, and only
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stores filenames, not paths, not even relative ones. As such, we can't have
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files with the same name, because they will conflict, and one will override the
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other.
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To avoid this situation, this script will find all cpp source files (we don't
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need to care about header-only things, those do not result in an object file),
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and will comb through them to find conflicting filenames.
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If a conflict is found, it will print all files that share the name, and will
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exit with an error at the end. It does not exit at the first duplicate, but will
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find and print all of them.
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If no conflict is found, the script just prints its status message and exits
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with zero."""
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import os
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import re
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import sys
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cpp_regex = re.compile('.*\.cpp')
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def find_duplicates(root):
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"""Search for files with the same basename, but in different directories in
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the tree under <root>. Prints a message for each conflict found, and
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returns a count of the number of non-unique basenames."""
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# Search the specified tree for matching basenames:
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basenames = {}
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for dir_path, dirs, files in os.walk(root):
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for file_name in files:
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if cpp_regex.match(file_name):
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if file_name not in basenames:
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basenames[file_name] = []
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basenames[file_name].append(dir_path)
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conflict_count = 0
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for file_name, dirs in basenames.items():
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# Prune unique basenames from the dict:
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if len(dirs) <= 1:
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continue
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conflict_count += 1
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# Print info about basenames with conflicts:
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print(f"Conflict found for file name '{file_name}':")
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for root in dirs:
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path = os.path.join(root, file_name)
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print(f' -> {path}')
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return conflict_count
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def main(args):
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print('Searching for conflicting filenames...')
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exit_code = 0
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for path in args:
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exit_code += find_duplicates(path)
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if exit_code != 0:
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sys.exit(exit_code)
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print('No filename conflicts found.')
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if __name__ == "__main__":
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main(sys.argv[1:])
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