Add Qukeys "tap-repeat" feature

This change gives Qukeys the ability to repeat a primary keycode by
tapping the key, then immediately pressing and holding it. While doing
this, the extra release and press of the key are suppressed, so it
looks to the host just like a simple press-and-hold event, which is
particularly nice for users of macOS apps that use Cocoa, where
holding letter keys is the "standard" way of accessing accented
characters.

Signed-off-by: Michael Richters <gedankenexperimenter@gmail.com>
pull/1024/head
Michael Richters 4 years ago
parent d97221c5a1
commit 94d26b8cb8
No known key found for this signature in database
GPG Key ID: 1288FD13E4EEF0C0

@ -1,6 +1,6 @@
/* -*- mode: c++ -*-
* Kaleidoscope-Qukeys -- Assign two keycodes to a single key
* Copyright (C) 2017-2019 Michael Richters
* Copyright (C) 2017-2020 Michael Richters
*
* This program is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
@ -153,7 +153,6 @@ EventHandlerResult Qukeys::beforeReportingState() {
// -----------------------------------------------------------------------------
// This function contains most of the logic behind Qukeys. It gets called after
// an event gets added to the queue, and again once per cycle. It returns `true`
// if nothing more should be done, either because the queue is empty, or because
@ -174,8 +173,22 @@ bool Qukeys::processQueue() {
// If that first event is a key release, it can be flushed right away.
if (event_queue_.isRelease(0)) {
flushEvent(Key_NoKey);
return true;
// We can't unconditionally flush the release event, because it might be
// second half of a tap-repeat event. If the queue is full, we won't bother to
// check, but otherwise, ift `tap_repeat_.addr` is set (and matches), we call
// `shouldWaitForTapRepeat()` to determine whether or not to flush the key
// release event.
if (event_queue_.isFull() ||
queue_head_addr != tap_repeat_.addr ||
!shouldWaitForTapRepeat()) {
flushEvent(Key_NoKey);
return true;
}
// We now know that we're waiting to determine if we're getting a tap-repeat
// sequence, so we can't flush the release event at the head of the queue.
// Warning: Returning false here is only okay because we already checked to
// make sure the queue isn't full.
return false;
}
// We now know that the first event is a key press. If it's not a qukey, or if
@ -237,6 +250,13 @@ bool Qukeys::processQueue() {
if (next_keypress_index == 0 || overlap_threshold_ == 0) {
Key event_key = qukey_is_spacecadet ?
queue_head_.alternate_key : queue_head_.primary_key;
// A qukey just got released in primary state; this might turn out to be
// the beginning of a tap-repeat sequence, so we set the tap-repeat
// address and start time to the time of the initial press event before
// flushing it from the queue. This will come into play when processing
// the corresponding release event later.
tap_repeat_.addr = queue_head_addr;
tap_repeat_.start_time = event_queue_.timestamp(0);
flushEvent(event_key);
return true;
}
@ -420,6 +440,100 @@ bool Qukeys::isKeyAddrInQueueBeforeIndex(KeyAddr k, uint8_t index) const {
}
// This question gets called early in `processQueue()` if a key release event is
// at the head of the queue, and the `tap_repeat_.addr` is the same as that
// event's KeyAddr. It returns true if `processQueue()` should wait for either
// subsequent events or a timeout instead of proceeding to flush the key release
// event immediately, and false if it is still waiting. It assumes that
// `event_queue_[0]` is a release event, and that `event_queue_[0].addr ==
// tap_repeat_.addr`. (The latter should only be set to a valid KeyAddr if a qukey
// press event has been flushed with its primary Key value, and could still
// represent the start of a double-tap or tap-repeat sequeunce.)
bool Qukeys::shouldWaitForTapRepeat() {
// First, we set up a variable to store the queue index of a subsequent press
// of the same qukey addr, if any.
uint8_t second_press_index = 0;
// Next, we search the event queue (starting at index 1 because the first
// event in the queue is known), trying to find a matching sequeunce for
// either a double-tap, or a tap-repeat.
for (uint8_t i{1}; i < event_queue_.length(); ++i) {
if (event_queue_.isPress(i)) {
// Found a keypress event following the release of the initial primary
// qukey.
if (event_queue_.addr(i) == tap_repeat_.addr) {
// The same qukey toggled on twice in a row, and because of the timeout
// check below, we know it was quick enough that it could represent a
// tap-repeat sequence. Now we update the start time (which had been set
// to the timestamp of the first press event) to the timestamp of the
// first release event (currently at the head of the queue), because we
// want to compare the release times of the two taps to determine if
// it's actually a double-tap sequence instead (otherwise it could be
// too difficult to tap it fast enough).
tap_repeat_.start_time = event_queue_.timestamp(0);
// We also record the index of this second press event. If it turns out
// that we've got a tap-repeat sequence, we want to silently suppress the
// first release and second press by removing them from the queue
// without flushing them. We don't know yet whether we'll be doing so.
second_press_index = i;
} else {
// Some other key was pressed. For it to be a tap-repeat sequence, we
// require that the same key be pressed twice in a row, with no
// intervening presses of other keys. Therefore, we can return false to
// signal that the release event at the head of the queue can be
// flushed.
return false;
}
} else if (event_queue_.addr(i) == tap_repeat_.addr) {
// We've found a key release event in the queue, and it's the same key as
// the qukey at the head of the queue, so this is the second release that
// has occurred before timing out (see below for the timeout
// check). Therefore, this is a double-tap sequence (the second release
// happened very close to the first release), not a tap-repeat, so we
// clear the tap-repeat address, and return false to trigger the flush of
// the first release event.
tap_repeat_.addr = KeyAddr{KeyAddr::invalid_state};
return false;
}
}
// We've now searched the queue. Either we found only irrelevant key release
// events (for other keys that were pressed before the sequence began), or we
// found only a second key press event of the same qukey (but not a double
// tap). Next, we check the timeout. If we didn't find a second press event,
// the start time will still be that of the initial key press event (already
// flushed from the queue), but if the second press has been detected, the
// start time will be that of the key release event currently at the head of
// the queue.
if (Runtime.hasTimeExpired(tap_repeat_.start_time, tap_repeat_.timeout)) {
// Time has expired. The sequence represents either a single tap or a
// tap-repeat of the qukey's primary value. Either way, we can clear the
// stored address.
tap_repeat_.addr = KeyAddr{KeyAddr::invalid_state};
if (second_press_index > 0) {
// A second press was found (but it's release didn't come quick enough to
// be a double tap), so this is a tap-repeat event. To turn it into a
// single key press and hold, we need to remove the second press event and
// the first release event from the queue without flushing the
// events. Order matters here!
event_queue_.remove(second_press_index);
event_queue_.remove(0);
} else {
// The key was not pressed again, so the single tap has timed out. We
// return false to let the release event be flushed.
return false;
}
}
// We haven't found a double-tap sequence, and the timeout hasn't expired, so
// we return true to signal that we should just wait until we get another
// event, or until time runs out.
return true;
}
// -----------------------------------------------------------------------------
// This function is here to provide the test for a SpaceCadet-type qukey, which

@ -1,6 +1,6 @@
/* -*- mode: c++ -*-
* Kaleidoscope-Qukeys -- Assign two keycodes to a single key
* Copyright (C) 2017-2019 Michael Richters
* Copyright (C) 2017-2020 Michael Richters
*
* This program is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
@ -81,6 +81,17 @@ class Qukeys : public kaleidoscope::Plugin {
hold_timeout_ = hold_timeout;
}
// Set the timeout (in milliseconds) for the tap-repeat feature. If a qukey is
// tapped twice in a row in less time than this amount, it will allow the user
// to hold the key with its primary value (unless it's a SpaceCadet type key,
// in which case it will repeat the alternate value instead). This requires a
// quick tap immediately followed by a press and hold, and will result in a
// single press-and-hold on the host system. If a double tap is done instead,
// it will result in two independent taps.
void setMaxIntervalForTapRepeat(uint8_t ttl) {
tap_repeat_.timeout = ttl;
}
// Set the percentage of the duration of a subsequent key's press that must
// overlap with the qukey preceding it above which the qukey will take on its
// alternate key value. In other words, if the user presses qukey `Q`, then
@ -190,6 +201,14 @@ class Qukeys : public kaleidoscope::Plugin {
bool isDualUseKey(Key key);
bool releaseDelayed(uint16_t overlap_start, uint16_t overlap_end) const;
bool isKeyAddrInQueueBeforeIndex(KeyAddr k, uint8_t index) const;
// Tap-repeat feature support.
struct {
KeyAddr addr{KeyAddr::invalid_state};
uint16_t start_time;
uint8_t timeout{200};
} tap_repeat_;
bool shouldWaitForTapRepeat();
};
// This function returns true for any key that we expect to be used chorded with

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